What are the responsibilities and job description for the R&D Analytical Chemistry Internship position at Oakwood Labs?
The R&D Internship will guide you through the application of analytical chemistry as it relates to an industrial pharmaceutical laboratory setting. It will provide you with hands-on experience testing pharmaceutical samples with analytical instrumentation and interpreting the data generated. This internship will also provide coaching and mentoring opportunities, involvement with multidisciplinary teams working on pharmaceutical product development, and presenting a summary of your work to the R&D team.
We are looking for Bachelors students who have completed at least their junior year majoring in Chemistry, Biochemistry, or similar degrees. Candidates should have strong communication skills, an eagerness to learn, team focus, and high self-motivation.
The R&D Internship will provide you with hands-on experience developing polymer based pharmaceutical products with exposure to pre-formulation experiments, product formulation testing, and process scale-up ranging from laboratory to pilot scale. This internship will also provide opportunities for coaching and mentoring, involvement with multidisciplinary teams working on pharmaceutical product development, and presenting a summary of your work to the R&D team. We are looking for Bachelors students who have completed at least their junior year majoring in Chemical Engineering, Biomedical Engineering, or similar degrees. Candidates should have strong communication skills, an eagerness to learn, team focus, high self-motivation, and a desire to work in a laboratory setting.
- The typical summer term is 10 to 12 weeks beginning in May
- The internship will be in-person in the Cleveland, Ohio area
- Housing assistance, if needed, includes a monthly stipend
- Temporary housing can be coordinated through Oakwood, but is the students responsibility
- Transportation is the students responsibility
- Full time availability (40 hours per week)
- Pay rate is $20.00/hr
Salary : $20